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Why do we take the Center of mass to be on the right side rather than on the left?
A uniform circular disc of radius 4a with a circular hole of radius 2a made in the disc.
The mass of L is m and a particle of mass km is now fixed to L at the point P. The system is now suspended from the point S and hangs freely in equilibrium. The diameter ST makes an angle a with the downward vertical through S, where tana=5/6
Find the value of K
Disc before adding weight km at point P has a mass m of coordinates (10/3,0).
https://s26.postimg.org/qczk9oc3t/image.jpg[URL]https://s26.postimg.org/lsdduqseh/image.jpg
A uniform circular disc of radius 4a with a circular hole of radius 2a made in the disc.
The mass of L is m and a particle of mass km is now fixed to L at the point P. The system is now suspended from the point S and hangs freely in equilibrium. The diameter ST makes an angle a with the downward vertical through S, where tana=5/6
Find the value of K
Disc before adding weight km at point P has a mass m of coordinates (10/3,0).
https://s26.postimg.org/qczk9oc3t/image.jpg[URL]https://s26.postimg.org/lsdduqseh/image.jpg
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