Finding length of minute hand of clock

[QuantumCurt]

Homework Statement

The minute hand of a clock travels 6.28 inches in 15 minutes. Find the length of the minute hand. Approximate to the nearest inch, if necessary.

The Attempt at a Solution

I figured the arc length to be [itex]\frac{\pi}{2}[/itex] because it's traveled one quarter of the way around the clock.

I set the equation up like this-

[tex]\frac{\pi/2}{15}x=6.28[/tex]

Then I solve for x by multiplying by the reciprocal, and I'm getting 59.97.

This was a question on a test I had earlier today, and when I did it then, I got approximately 15.001 or something like that. That answer didn't seem right to me, and the answer I'm getting now doesn't seem anymore right. I can't remember exactly how I set it up. What am I doing wrong? The rest of the test was simple, this was the only one that threw me off.

 

[Mark44]

Homework Statement

The minute hand of a clock travels 6.28 inches in 15 minutes. Find the length of the minute hand. Approximate to the nearest inch, if necessary.

The Attempt at a Solution

I figured the arc length to be [itex]\frac{\pi}{2}[/itex] because it's traveled one quarter of the way around the clock.

I set the equation up like this-

[tex]\frac{\pi/2}{15}x=6.28[/tex]

Then I solve for x by multiplying by the reciprocal, and I'm getting 59.97.

This was a question on a test I had earlier today, and when I did it then, I got approximately 15.001 or something like that. That answer didn't seem right to me, and the answer I'm getting now doesn't seem anymore right. I can't remember exactly how I set it up. What am I doing wrong? The rest of the test was simple, this was the only one that threw me off.

Why are you dividing by 15?

 

[QuantumCurt]

Why are you dividing by 15?

I had been trying to use a linear speed formula to find the radius, but as I've thought about it more it made less and less sense.

Should I have found the circumference by multiplying the 6.28 by 4 to get the entire circumference of the circle, then divide by 2pi?

 

[verty]

I had been trying to use a linear speed formula to find the radius, but as I've thought about it more it made less and less sense.

Should I have found the circumference by multiplying the 6.28 by 4 to get the entire circumference of the circle, then divide by 2pi?

The pertinent fact is that circumference = 2π * radius; from this you can find the length of one quarter of the circumference. In general you want to find a formula including the unknown and the known. This is the algebraic way of thinking - get a formula that for conceptual reasons you know is correct, then plug in the numbers with less chance of making a mistake.

 

[lalo_u]

I agreed Verty.

You may start with the definitlion of [itex]\pi=\frac{\mathcal{C}}{2R}[/itex], where [itex]\mathcal{C}[/itex] is the circumference lenght.

Then, since you have the length of a quarter of the circumference, can clear the radio.

 

[HallsofIvy]

All that is relevant is that [itex](\pi/2)r[/itex] is the length of a quarter circle arc. The time it takes to travel that is irrelevant. You only need the fifteen minutes to know that the minute hand traveled a quarter circle.

 

[QuantumCurt]

So then I would want to set it up like-6.28(4)/2pi? So...approximately 8 inches?

 

[lalo_u]

So then I would want to set it up like-6.28(4)/2pi? So...approximately 8 inches?

You're dividing a quarter of an arc between a full arc angle...

 

[Mark44]

So then I would want to set it up like-6.28(4)/2pi? So...approximately 8 inches?

6.28 ≈ 2##\pi##, so the expression above simplifies to approximately 4.