- #1
cragar
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Homework Statement
Find the E field of a parallel plate capacitor tilted at 45 degrees from vertical and moving at a speed v. each plate has plus or minus [itex] \sigma_0 [/itex] for charge density.
The Attempt at a Solution
Well the E field in rest frame would be [itex] E= \frac{\sigma_0}{\epsilon_0} [/itex]
Now when we move the plates at a speed v, we will have length contraction that will increase the charge density. But it will only increase the x component of the plate, since length contraction only occurs in the direction of motion .
So I think the new E field will be [itex] E= \frac{\sigma_0cos(45)\gamma}{\epsilon_0} [/itex]
And then it asks if the E field while the plates are moving will still be perpendicular to the plates, and i think it will be.