- #1
cmcdonald29
- 4
- 0
1.)Two charges are fixed in location: charge q1= +8e is located at the origin and charge q2= -2e is located on the x-axis at x=L. At what point can a proton be placed so that it has net zero force acting on it?
2.)F=kq1q2/r^2
3.)I tried to do F=0
K = 8.988 X 10^9 (constant)
q1 = (8 protons) X (1.602 X 10^-19) ---> (individual charge of one proton)
q2 = (2 electrons) X (1.602 X 10^-19)
I used the equation above then to find r^2; however, as you can see F = 0 X r^2 would give me zero and you cannot divide by 0 to find r. I am confused on how to find the distance.
2.)F=kq1q2/r^2
3.)I tried to do F=0
K = 8.988 X 10^9 (constant)
q1 = (8 protons) X (1.602 X 10^-19) ---> (individual charge of one proton)
q2 = (2 electrons) X (1.602 X 10^-19)
I used the equation above then to find r^2; however, as you can see F = 0 X r^2 would give me zero and you cannot divide by 0 to find r. I am confused on how to find the distance.