- #1
Albert1
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$m,n,p,q\in N$
$m\neq n\neq p\neq q$
and $(7-m)(7-n)(7-p)(7-q)=4$
find:$7m+7n+7p+7q=?$
$m\neq n\neq p\neq q$
and $(7-m)(7-n)(7-p)(7-q)=4$
find:$7m+7n+7p+7q=?$
Albert said:$m,n,p,q\in N$
$m\neq n\neq p\neq q$
and $(7-m)(7-n)(7-p)(7-q)=4$
find:$7m+7n+7p+7q=?$
The equation is $(7-m)(7-n)(7-p)(7-q)=4$, where m, n, p, and q are the four different natural numbers.
You can solve the equation by substituting different values for m, n, p, and q. If the result is equal to 4, then the set of numbers satisfies the equation.
No, the equation only works with natural numbers, which are positive whole numbers starting from 1.
No, the equation is commutative, meaning the order of the numbers does not affect the result.
The number 7 is used as a constant in the equation to ensure that the result is always equal to 4. It is also a part of the natural number series and serves as a placeholder for the four different numbers in the equation.