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Homework Statement
A practical current source has a current of [tex]22 A[/tex]. Loading the source with [tex]50 \Omega[/tex] results in terminal voltage of [tex]390.3 V[/tex]. Obtain the source constants, I and R.
Homework Equations
[tex]V=I\times R[/tex]
The Attempt at a Solution
In my clumsy picture below, shouldn't [tex]I_{load}[/tex] be replaced by the [tex]I[/tex] of the "practical current source"? That is, isn't a "practical current source" as a black box, and we can only "see" the outside current?
[PLAIN]http://img51.imageshack.us/img51/1466/dsc01001ni.jpg
Only if I take the current outside as [tex]I_{load}[/tex] (and not as the [tex]I[/tex] itself) do I get the correct solution:
[tex]I_{load}=\frac{V}{R_{load}}=\frac{390.3V}{50 \Omega}=7.806 A[/tex]
[tex]R=\frac{V}{I_R}=\frac{V}{I-I_{load}}=\frac{390.3 V}{22A - 7.806 A}\dot{=}27.5 \Omega[/tex]
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