Find area of the shaded part in the given diagram

  • #1
chwala
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Homework Statement
See attached.
Relevant Equations
O level Math
1715334511888.png


1715334531765.png



In my working, i have the following approach;

1715334601803.png


Using area of semi -circle and area of sector concept;

##x +z = \dfrac{9π}{2}##
##x +y = \dfrac{9π}{2}##
##z+p = \dfrac{9π}{2}##

On solving the simultaneous equations,
##⇒x=p##

then,

##x=\dfrac {9π}{4} - \left(\dfrac{1}{2} ×3 ×3\right) = \dfrac{9π-18}{4}##

##⇒ p = \dfrac{9π-18}{4}##

Therefore,

##m+x+p = \dfrac{36-9π}{2} + \dfrac{9π-18}{4} + \dfrac{9π-18}{4}##

##=\dfrac{36-9π}{2} +2\left( \dfrac{9π-18}{4} \right)##

##=\left(\dfrac{36}{2} - 4 .5π+ 4 .5π - 9 \right)= 18-9=9##

Unless there is a better approach. Good day and cheers.
 

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  • #2
Using symmetry of the individual shaded areas respect to the diagonal lines may be a simpler solution.

0C92EEC6-C5AB-46E3-A16F-247B346BB812.jpeg
 
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  • #3
chwala said:
Homework Statement: See attached.
Relevant Equations: O level Math

Unless there is a better approach.
An alternative approach:
1715342365041.png


x=x'
m=m'
So, the area is the triangle on the right, i.e., quarter of the square.

EDIT: x-posted with #2.
 
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