- #1
haael
- 539
- 35
Is it possible to express fermion annihilation operator as a function of position and momentum?
I've seen on Wikipedia the formula for boson annihilation operator:
[tex]
\begin{matrix} a &=& \sqrt{m\omega \over 2\hbar} \left(x + {i \over m \omega} p \right) \\ a^{\dagger} &=& \sqrt{m \omega \over 2\hbar} \left( x - {i \over m \omega} p \right) \end{matrix}
[/tex]
But what about fermions? Is it possible to get anticommutation relations from canonical relations alone, or is it necessary to postulate something else?
I've seen on Wikipedia the formula for boson annihilation operator:
[tex]
\begin{matrix} a &=& \sqrt{m\omega \over 2\hbar} \left(x + {i \over m \omega} p \right) \\ a^{\dagger} &=& \sqrt{m \omega \over 2\hbar} \left( x - {i \over m \omega} p \right) \end{matrix}
[/tex]
But what about fermions? Is it possible to get anticommutation relations from canonical relations alone, or is it necessary to postulate something else?