- #1
JamesGoh
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Homework Statement
Express [itex]\frac{1}{(2n+1)!}[/itex] as the following
[itex]\frac{(-2)^{n}n!x^{2n+1}}{(2n+1)!}[/itex]
where 0 <= n <= infinity
Homework Equations
The double factorial for odd integers is
(2n+1)! = (2n+1)(2n-1)(2n-3)...1 where 0 <= n <= infinity
The Attempt at a Solution
Visited this website http://mathworld.wolfram.com/DoubleFactorial.html and scrolled
down to the expression for
[itex](-2n-1)! = \frac{(-1)^{n}2^{n}n!}{2n!}[/itex]
performing the sign inverse, i got
[itex](2n+1)! = \frac{(1)^{n}-2^{n}n!}{-2n!}[/itex]