Exploring Momentum Conservation in Cart Motion

In summary, according to the website, when a fan is used to blow air into a sail attached to a cart, the entire cart system remains motionless. However, this contradicts the law of conservation of momentum, as the air particles bouncing off the sail should cause the cart to move in the opposite direction. This is because the force of the air on the sail is not perfectly coupled with the force of the air on the fan blades, resulting in a net force on the cart. This is demonstrated by a similar example using tennis balls and a car, where the car moves in the same direction as the balls. Therefore, the initial approach of using conservation of momentum to explain the motion of the cart is flawed.
  • #1
#H34N1
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Homework Statement


http://www.physics.umd.edu/lecdem/outreach/QOTW/arch3/a046.htm
According to the site, when a fan is blowing air into a sail, the entire cart system remains motionless.
Why doesn't the following approach work:
Since there are no net external forces acting on the entire cart, momentum is conserved. The air particles are bombarding the sail and are bouncing back with a momentum of p_f. Since momentum is conserved, the cart must then move in the opposite direction with a momentum of p_0+p_f. Because the sail is attached to the car, the car itself moves in the direction in which the fan is blowing.

What's wrong with this?

Also, in another example where a person throws tennis balls leftward at a rigid surface that is perpendicularly attached to a cart, the cart itself moves leftward.

What is the difference here?
Thanks

Homework Equations


p_i = p_f
[tex]F_{net}\Delta t=m\Delta v[/tex]


The Attempt at a Solution


(Essentially given in part 1)
 
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  • #2
#H34N1 said:

Homework Statement


http://www.physics.umd.edu/lecdem/outreach/QOTW/arch3/a046.htm
According to the site, when a fan is blowing air into a sail, the entire cart system remains motionless.
Why doesn't the following approach work:
Since there are no net external forces acting on the entire cart, momentum is conserved. The air particles are bombarding the sail and are bouncing back with a momentum of p_f. Since momentum is conserved, the cart must then move in the opposite direction with a momentum of p_0+p_f. Because the sail is attached to the car, the car itself moves in the direction in which the fan is blowing.

What's wrong with this?

Also, in another example where a person throws tennis balls leftward at a rigid surface that is perpendicularly attached to a cart, the cart itself moves leftward.

What is the difference here?
Thanks

Homework Equations


p_i = p_f
[tex]F_{net}\Delta t=m\Delta v[/tex]


The Attempt at a Solution


(Essentially given in part 1)

Can you please re-assess the second system so I know exactly what's happenin'?

And, as for the first part, the fan exerts a force on the air the drives the air to the right, while the force exerted by the air on the fan drives the fan and, consequently, the cart to the left. But, this propelled air then strikes the sail, exerting a force equal and opposite that it imposed on the fan during part (1) of motion. So, essentially, the cart will stay where it begins.
 
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  • #3
asleight said:
And, as for the first part, the fan exerts a force on the air the drives the air to the right, while the force exerted by the air on the fan drives the fan and, consequently, the cart to the left. But, this propelled air then strikes the sail, exerting a force equal and opposite that it imposed on the fan during part (1) of motion. So, essentially, the cart will stay where it begins.
But the OP makes the very good point that if the wind bounces off the sail and goes backward then isn't this equivalent to having the fan pointing backward?

Imagine it with tennis balls - if you sit inside a car and throw balls at the windscreen and they bounce off and go out of the back of the car with the same velocity - this is the same as throwing the balls backward with that velocity.
 
  • #4
asleight said:
Can you please re-assess the second system so I know exactly what's happenin'?

And, as for the first part, the fan exerts a force on the air the drives the air to the right, while the force exerted by the air on the fan drives the fan and, consequently, the cart to the left. But, this propelled air then strikes the sail, exerting a force equal and opposite that it imposed on the fan during part (1) of motion. So, essentially, the cart will stay where it begins.
This assumes a perfect coupling of the force of the air from the fan blades and the sail. Does any of the air moved by the fan have a tangential component? If so, won't the cart experience a net force tending to move it toward the left?
 
  • #5
mgb_phys said:
But the OP makes the very good point that if the wind bounces off the sail and goes backward then isn't this equivalent to having the fan pointing backward?

Imagine it with tennis balls - if you sit inside a car and throw balls at the windscreen and they bounce off and go out of the back of the car with the same velocity - this is the same as throwing the balls backward with that velocity.

Center of mass must remain constant.

Removed so OP can try.
 
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  • #6
Yes that's why the paradox is wrong - the fan is 'sucking' the air from behind the cart and then blowing it back at the same velocity. I hoped the OP would contribute something before we revealed that.
 

Related to Exploring Momentum Conservation in Cart Motion

1. What is momentum conservation and why is it important in cart motion?

Momentum conservation is a fundamental principle in physics that states the total momentum of a closed system remains constant. In cart motion, this means that the total momentum before and after a collision or interaction between carts will be the same. This principle is important because it helps us understand and predict the motion of objects in a system, and is a crucial concept in the study of mechanics.

2. How is momentum calculated and measured in cart motion experiments?

Momentum is calculated by multiplying an object's mass by its velocity. In cart motion experiments, we can measure the mass of the carts using a balance scale, and measure their velocity using a motion sensor or by timing the carts as they travel a known distance. These values can then be used to calculate the momentum of each cart before and after a collision or interaction.

3. Can momentum be lost or gained in a cart motion experiment?

No, momentum is always conserved in a closed system. This means that the total momentum of the carts before and after a collision or interaction will be the same. However, the distribution of momentum among the carts may change, with some carts gaining momentum and others losing it.

4. How does the mass and velocity of the carts affect momentum conservation in cart motion?

According to the equation for momentum (p = mv), an increase in mass will result in an increase in momentum, while an increase in velocity will result in a larger change in momentum. Therefore, changes in mass and velocity will affect the distribution of momentum among the carts in a collision or interaction.

5. What are some real-world applications of momentum conservation in cart motion?

Momentum conservation is a fundamental principle in physics that applies to a wide range of systems, including cart motion. It is used to understand and analyze collisions in sports, traffic accidents, and even in space travel. It also plays a crucial role in the design and engineering of vehicles and structures to ensure their safety and stability.

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