Expected value of variance of Hamiltonian in coherent states

In summary, the conversation is about finding the expected value of the variance of energy in coherent states, but there is uncertainty due to the non-hermitian and non-commutative nature of the lowering and raising operators. The solution involves using the commutator property to reduce the calculation to a simpler form.
  • #1
graviton_10
5
1
Homework Statement
Find the variance of the energy in coherent state |ɑ>.
Relevant Equations
<ΔH> = <ɑ| HH |ɑ>
I am trying to find the expected value of the variance of energy in coherent states. But since the lowering and raising operators are non-hermitian and non-commutative, I am not sure if I am doing it right. I'm pretty sure my <H>2 calculation is right, but I'm not sure about <H2> calculation.

Here is my solution:
 

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  • #2
1677335473758.png


Check the step circled in orange. ##a^\dagger## and ##a## don't commute.
 
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  • #3
Yes, but how to do it the right way?
 
  • #4
graviton_10 said:
Yes, but how to do it the right way?
Please post the steps for how you reduced ##\langle \alpha | (a^{\dagger} a)^2|\alpha \rangle## to ##|\alpha^*\alpha|^2 \langle \alpha | \alpha \rangle##. That way, we can help you see where you made a mistake.
 
  • #5
So, I used the fact that the commutator of a and a dagger is 1. Does it look good now?
 

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  • #6
That looks good.
 

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