Evaluation of definite integral

In summary, the conversation discusses the evaluation of the integral int(-inf,inf)(x/(x^3+1)). The participants consider different approaches, such as finding the residues and using a contour integral. However, there is uncertainty about how to handle the singularity at -1 on the real line. It is suggested to check if the integral actually exists/converges before worrying about contours. In the end, it is noted that the integral is not convergent and cannot be evaluated using the given methods.
  • #1
NT123
28
0

Homework Statement

Need to evaluate int(-inf,inf)(x/(x^3+1)).



Homework Equations





The Attempt at a Solution

I don't believe finding the residues will be a problem. However, the integral is over the whole real line, and there is a singularity at -1 on the real line, so I'm not sure how to draw an appropriate contour to integrate around. Am I supposed to integrate over a keyhole contour avoiding the singularity at -1 from the right and then from the left? Any help / advice will be much appreciated.
 
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  • #2
You might want to check if the integral actually exists/converges before worrying about contours.
 
  • #3
gabbagabbahey said:
You might want to check if the integral actually exists/converges before worrying about contours.

My book says it is equal to pi/sqrt(3) :)
 
  • #4
NT123 said:
My book says it is equal to pi/sqrt(3) :)

Hmm...

[tex]\lim_{\epsilon\to 0} \left[\int_{-\infty}^{-1-\epsilon} \frac{x}{x^3+1}dx+\int^{\infty}_{-1+\epsilon} \frac{x}{x^3+1}dx\right]=\frac{\pi}{\sqrt{3}}[/tex]

But, I don't think you can say that is the same thing as [itex]\int_{-\infty}^{\infty} \frac{x}{x^3+1}dx[/itex]. Mathematica seems to agree with me, that the integral doesn't converge. I don't think [itex]x=-1[/itex] is a removable singularity.
 
  • #5
Yeah... MATLAB seems to say the same thing.
 

Related to Evaluation of definite integral

1. What is a definite integral?

A definite integral is a mathematical concept used to find the area under a curve between two points on a graph. It is represented by the symbol ∫ and is calculated by evaluating the function at those two points and taking the difference between them.

2. How is the definite integral different from the indefinite integral?

A definite integral has specific limits of integration, which means that it is calculated for a specific interval on the graph. On the other hand, an indefinite integral does not have any limits of integration and represents the general antiderivative of a function.

3. What is the purpose of evaluating a definite integral?

Evaluating a definite integral allows us to find the exact area under a curve, which has many real-world applications. It can also be used to calculate displacement, velocity, and acceleration in physics and to find probabilities in statistics.

4. What are the different methods for evaluating a definite integral?

There are several methods for evaluating a definite integral, including the Riemann sum, the Trapezoidal rule, and Simpson's rule. These methods use different approximations to calculate the area under the curve.

5. Can a definite integral have a negative value?

Yes, a definite integral can have a negative value. This occurs when the function being integrated has negative values within the given interval, which results in the area under the curve being subtracted from the total area.

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