- #1
roya
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Homework Statement
The problem is translated from a different language, so I hope I am not missing anything.
I need to estimate the redshift of the photon gas in the universe, at the time of transition from radiation to matter domination.
Cosmological parameters:
[tex] k=0 [/tex] (meaning a flat universe)
[tex] \Omega_\Lambda=0.7 [/tex]
[tex] H_0=71\frac{km}{s\cdot{Mpc}} [/tex]
also it is mentioned that [tex]\rho_{matter} \propto R^{-3} ~,~ \rho_{radiation} \propto R^{-4}[/tex]
Homework Equations
Friedmann equation:
[tex]H^2=\left(\frac{\dot{R}}{R}\right)^2 = \frac{8}{3}\pi G\rho - \frac{kc^2}{R^2} + \frac{\Lambda}{3}[/tex]
redshift in terms of universe scale factor
[tex]1+z_{eq}=\frac{R_0}{R(t)}[/tex]
and also the definition of the omegas:
[tex]\Omega_m=\frac{\rho}{\frac{8}{3} \pi GH^2}[/tex]
[tex]\Omega_\Lambda=\frac{\Lambda}{3H^2}[/tex]
The Attempt at a Solution
I am not completely sure that this is the right approach, but it's the only thing that comes to mind. Basically what I am trying to do is find the scale factor R(t) in terms of R0 and t0, and just plug it into the redshift equation. In a flat universe (k=0) [tex]\Omega_m + \Omega_\Lambda = 1 [/tex] (which is derived easily using the friedmann equation), so [tex]\Omega_m=0.3[/tex]
This gives me [tex]H=\frac{\dot{R}}{R}[/tex] in terms of [tex]\rho[/tex].
but this is where i get confused. If I knew the proportionality relation between [tex]\rho (t)[/tex] and [tex]R(t)[/tex] then I could have solved the differential equation and find R..
[tex]\rho=\rho_{matter} + \rho_{radiation}[/tex], so if either matter or radiation density were dominant, I would use the dominant parameter, but the solution is for a time where they are equal... and if i try to equate them and find the total density that way, I get very awkward results... I am pretty sure that this is wrong and that I am lacking some basic understanding... I really hope someone can help me out here.One more thing that really confuses me, is if I try to find R(t) using [tex]\Omega_\Lambda[/tex].
This gives me a differential equation for R, which I can solve
[tex]\frac{\dot{R}}{R}=\sqrt{\frac{\Lambda}{3\Omega_\Lambda}}[/tex]
[tex]R(t)=R_0 e^{\sqrt{\frac{\Lambda}{3\Omega_\Lambda}}(t-t_0)}[/tex]
I guess t0 I can find using the Hubble constant [tex]t_0=H_0^{-1}[/tex]
but this doesn't make sense.. why is the proportional relation between the densities and the scale factor is given if not used... and of course matter-radiation equality is not taken into consideration ..
Very confused
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