EMF Generated When Magnet Moves Linearly Across Its Field

[Harsha Kumar]

Does an emf create across the body of a magnet when the magnet is linearly moving across its own field.

If ABCD is a rectangular magnet of thickness t, AB is the north pole and CD is the south pole. If the magnet moves in the direction of t, that is perpendicular to ABCD plane, will there be an emf generated between the faces AC and BD?

 

[Matterwave]

You can't have the magnet move with respect to itself. If you are asking for the electric field on the faces of the magnet itself, then you can simply work in the rest frame of the magnet. In that frame, there is no electric field. In a Lorentz boosted frame, e.g. if I am standing still as the magnet moved passed me, then I will see an electric field.

 

[Harsha Kumar]

Matterwave: But this is happening when a magnet rotates, like in the Faraday disc.

 

[Matterwave]

A rotating frame is different than a inertial frame. You are talking about a magnet undergoing uniform linear motion are you not?

 

[sardar]

Yes, there will be an emf (electromotive force) generated between the faces AC and BD when the magnet is linearly moving across its own field. This phenomenon is known as magnetic induction or Faraday's law of induction.

When a magnet moves across its own magnetic field, the magnetic flux passing through the area between the faces AC and BD changes. This change in magnetic flux induces an electric field, which in turn creates an emf between the two faces.

The emf generated is directly proportional to the rate of change of magnetic flux, as described by Faraday's law. This means that the faster the magnet moves across its own field, the greater the emf generated between the two faces.

This concept is used in many practical applications, such as generators and transformers, where the motion of a magnet in a coil of wire produces an emf, which can then be converted into electrical energy.

In conclusion, yes, there will be an emf generated between the faces AC and BD when a magnet moves linearly across its own field, as described by Faraday's law of induction.