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projjal
- 39
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We can easily find from gauss's theorem(or otherwise) the field inside and outside a uniformly charged spherical shell.But i was wondering what would be the field on the surface of the shell.
The electric field on the surface of a uniformly charged spherical shell can be calculated using the formula E = Q/(4πε₀R²), where Q is the total charge on the shell, ε₀ is the permittivity of free space, and R is the radius of the shell.
The electric field on the surface of a uniformly charged spherical shell remains constant at all points on the surface, regardless of the distance from the center. This is because the charge is distributed evenly on the surface, resulting in a symmetrical electric field.
No, the electric field on the surface of a uniformly charged spherical shell can only be positive. This is because the direction of the electric field is always outward from the surface of the shell, regardless of the sign of the charge.
If the radius of the shell is doubled, the electric field on the surface will decrease by a factor of 4. This is because the surface area of the shell increases by a factor of 4, while the total charge and permittivity of free space remain the same.
No, the electric field on the surface of a uniformly charged spherical shell is not affected by the presence of other charges or objects nearby. This is because the electric field is only dependent on the total charge and radius of the shell, not on the presence of other objects.