- #1
DottZakapa
- 239
- 17
- Homework Statement
- A narrow copper wire of length L and radius b is attached to a wide copper wire of length L and radius 2b, forming one long wire of length 2L. This long wire is attached to a battery, and a current is flowing through it. If the electric field in the narrow wire is E, the electric field in the wide wire is
- Relevant Equations
- current
i've started from this I1=I2
then
I1= JA1=##\frac {E l} R##
I2= JA2=##\frac {E_2 l} R##
but can't get anything useful relating them. Am i forgetting any other useful formula?
I get as result E4
then
I1= JA1=##\frac {E l} R##
I2= JA2=##\frac {E_2 l} R##
but can't get anything useful relating them. Am i forgetting any other useful formula?
I get as result E4