Dynamics question about boy pulling himself up via pulley

In summary, a 45 kg boy stands on a 30 kg platform suspended by a rope passing over a stationary pulley. The tension in the rope is determined to be 86.25 N when the boy and the platform are at rest and the boy pulls on the rope with an acceleration of 1.5 m/s^2 upwards. Under these conditions, the force exerted by the platform on the boy is determined to be 86.25 N. After reaching and sustaining an upward velocity of 0.3 m/s, the power output of the boy required to sustain this velocity is calculated using the equation Power = Fv. The book's answer of 131.25 N for the force exerted by the platform
  • #1
misterc
5
0

Homework Statement


A 45 kg boy stands on 30 kg platform suspended by a rope passing over a stationary pulley that is free to rotate. The other end of the rope is held by the boy. The masses of the rope and pulley are negligible. Ignore the friction in the pulley.

a) If the rope and the boy are at rest, what is the tension in the rope?

The boy now pulls on the rope so that the acceleration of the boy and the platform is 1.5 m/s^2 upward.

b) What is the tension force in the rope under these new conditions?
c) Under these conditions, what is the force exerted by the platform on the boy?

After a short time, the boy and the platform reach and sustain an upward velocity of 0.3 m/s.

d) Determine the power output of the boy required to sustain this velocity.

Homework Equations



For a-c, we need Newton 2 ƩF = ma.
For d, Power = Fv

The Attempt at a Solution



The problem here is really only part c. The book's answer and my answer agree on the other parts. Unfortunately, the book is wrong often enough that I don't always trust their answer. So, I want confirmation.

Here's what I did. Free Body Diagram on boy yields:
1. Fn upwards (Platform on boy)
2. Ft upwards (boy pulls down on rope, and by Newton 3, his force is Ft upwards). From part b, Ft = 431.25 N
3. mg downwards
ma = 45 * 1.5
In equation form,
Fn + Ft - mg = ma
Fn = ma + mg - Ft = 45*1.5 + 45*10 - 431.25 = 86.25 N
Unfortunately, the book says 131.25 N. I'm guessing that they added the weight of the platform to the ma side of the equation. Who's right? If the book is, why add the weight of the platform to the ma side.
 
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  • #2
Your solution is correct.

ehild
 

Related to Dynamics question about boy pulling himself up via pulley

1. How does a pulley help a boy pull himself up?

A pulley helps a boy pull himself up by reducing the amount of force needed to lift his body weight. The pulley system redistributes the weight, making it easier for the boy to pull himself up.

2. What is the principle behind using a pulley?

The principle behind using a pulley is the conservation of energy. The effort force applied to one end of the rope is spread out over multiple supporting ropes, reducing the overall force needed to lift an object.

3. Is a single pulley system enough for the boy to pull himself up?

No, a single pulley system may not be enough for the boy to pull himself up. The ideal pulley system for lifting an object requires at least two pulleys, with one acting as the load-bearing pulley and the other as the effort pulley.

4. How does the boy's weight affect the pulley system?

The boy's weight affects the pulley system by increasing the tension in the rope. The heavier the boy, the more force will be required to lift him. It is important to ensure that the pulley system is strong enough to withstand the weight and force involved.

5. Can the boy pull himself up using a pulley if he is not strong enough?

Yes, the boy can still use a pulley to pull himself up even if he is not strong enough. The pulley system reduces the amount of force needed to lift his body weight, making it easier for him to pull himself up. However, if the boy is significantly weaker, he may still require assistance from another person or a stronger pulley system.

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