Dynamics - Motion in a Plane, Problem

In summary: For a parabola, x is NOT 2y for all t. The shape of the trajectory is a parabola.For part c:Using my equations, I calculated it to be 37.32m, which is not correct.How did you get that?In summary, the problem involves finding the equation for the trajectory of a 5000kg rocket launched at an angle of 44.7º with a thrust of 140,700N. The acceleration of the rocket is found to be 22.36m/s^2 (including gravity) and the x and y components of acceleration are 20 m/s^2 and 10 m/s^2, respectively. The distance x and
  • #1
doctorjuice
7
0

Homework Statement


A 5000kg rocket is launched at 44.7º with a thrust of 140,700N.
a. Find an equation y(x) that describes the rocket's trajectory.
b. Shape of trajectory?
c. At what elevation does the rocket reach the speed of sound, 330m/s?

Homework Equations


F=ma
The distance, acceleration, and velocity formulas.


The Attempt at a Solution



First, I found the acceleration = 22.36 m/s^2 (this is after including gravity).

I drew a triangle and calculated the acceleration's x and y components. acceleration of x comp. = 20 m/s^2. acceleration of y comp. = 10 m/s^2 (including gravity).

Using these acceleration x and y components, I found the x and y components for distance:
distance of x comp. = 2.486t. distance of y comp. = 1.131t.

For part a:
So, I wasn't sure exactly what they wanted for part a but this is what I did. The answer in the back of the book says y=(1/2)x, so I'm guessing they want the distance of y as a function of x (which is what the answer was). I'm not sure how to do that.

For part b:
I figured the shape of the trajectory would be parabolic since it is constantly accelerating. I thought trajectory was only a straight line if velocity was constant?

For part c:
Using my equations, I calculated it to be 37.32m, which is not correct.

Any help would be greatly appreciated, I'm doing these in preparation for a test and I really need to understand these type of problems. :smile:
 
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  • #2
doctorjuice said:
acceleration of x comp. = 20 m/s^2. acceleration of y comp. = 10 m/s^2 (including gravity).

Using these acceleration x and y components, I found the x and y components for distance:
distance of x comp. = 2.486t. distance of y comp. = 1.131t.
That doesn't look right. How did you calculate those?
For part a: I'm guessing they want the distance of y as a function of x (which is what the answer was).
Once you have correct expressions for x and y as functions of t, just eliminate t between them.
For part b:
I figured the shape of the trajectory would be parabolic since it is constantly accelerating. I thought trajectory was only a straight line if velocity was constant?
No. If y = f(t) and x = 2*f(t) then x = 2y for all t.
 

Related to Dynamics - Motion in a Plane, Problem

What is dynamics?

Dynamics is the branch of physics that deals with the study of motion and the forces that cause it.

What is motion in a plane?

Motion in a plane refers to the movement of an object in a two-dimensional space, such as a horizontal surface or a vertical plane.

What are some common problems in dynamics - motion in a plane?

Some common problems in dynamics - motion in a plane include projectile motion, circular motion, and motion under the influence of friction.

What is the difference between speed and velocity?

Speed is a scalar quantity that only indicates how fast an object is moving, while velocity is a vector quantity that includes both the speed and direction of motion.

How do we solve problems involving motion in a plane?

To solve problems involving motion in a plane, we can use mathematical equations such as Newton's laws of motion, kinematic equations, and vector addition to analyze the forces and motion of the object.

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