Distribution function of an ideal gas

In summary, the problem at hand is finding the equilibrium distribution function of an ideal gas on a planet with a gravitational potential, taking into account the mass and temperature of the gas as well as the planet's mass and radius. The resulting distribution function is a combination of the Maxwell-Boltzmann distribution and a factor accounting for the gravitational potential. In this case, the potential is dependent on the distance from the center of the planet and is infinite within the planet's radius. The correct distribution function to use is the Maxwell-Boltzmann distribution.
  • #1
gdumont
16
0
Hi,

I have the following problem to solve:

Consider a planet of radius [itex]R[/itex] and mass [itex]M[/itex]. The plante's atmosphere is an ideal gas of [itex]N[/itex] particles of mass [itex]m[/itex] at temperature [itex]T[/itex]. Find the equilibrium distribution function of the gas accounting for the gas itself and the gravitationnal potential of the planet.

Here are my thoughts

The equilibrium function of the gas alone is simply the Maxwell-Boltzmann distribution function [itex]f_0(\mathbf{v})[/itex], so the full distribution is just
[tex]
f(\vec{v})=f_0(\vec{v})e^{-U/kT}
[/tex]
where
[tex]
U=-\frac{GMm}{r}
[/tex]
is the gravitational potential and [itex]r[/itex] is the distance from the center of the planet to the molecule of velocity [itex]\vec{v}[/itex]. I'm not sure if I should replace [itex]r[/itex] by [itex]r-R[/itex] in [itex]U[/itex].

Can anyone confirm if I'm right or not?

Thanks
 
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  • #2
The gas molecules can't penetrate into the surface of the planet, so it makes sense for your model to be described by a potential which is
[tex]
U(r) = - \frac{GMm}{r} \,\,\, r > R
[/tex]
and [tex] U = \infty [/tex] for [tex] r < R [/tex].
 
  • #3
OK, but is the distribution function OK?
 
  • #4
Yes, the Maxwell-Boltzmann distribution is the correct one.
 

Related to Distribution function of an ideal gas

1. What is the distribution function of an ideal gas?

The distribution function of an ideal gas is a mathematical function that describes the probability of a gas molecule having a certain velocity. It is based on the Maxwell-Boltzmann distribution, which assumes that gas molecules in a container move randomly and independently of each other.

2. How is the distribution function of an ideal gas related to temperature?

The distribution function of an ideal gas is directly related to temperature. As temperature increases, the average velocity of gas molecules also increases, resulting in a broader distribution of velocities. This can be seen in the shape of the distribution function, which becomes flatter and wider at higher temperatures.

3. What is the significance of the distribution function in understanding the behavior of an ideal gas?

The distribution function is essential in understanding the behavior of an ideal gas because it provides information about the velocities and energies of individual gas molecules. This information can be used to calculate important thermodynamic properties such as pressure, temperature, and internal energy.

4. How does the distribution function change with different types of gases?

The distribution function of an ideal gas is the same for all types of gases, as long as they are at the same temperature. This is because the distribution function is based on the fundamental principles of kinetic theory, which apply to all gases regardless of their chemical composition.

5. Can the distribution function of an ideal gas be applied to real gases?

The distribution function of an ideal gas is a theoretical concept that assumes ideal conditions, such as perfectly elastic collisions between gas molecules. In real gases, these conditions may not hold, so the distribution function may not accurately describe the behavior of the gas. However, the concept of the distribution function can still be useful in analyzing the behavior of real gases, especially at low pressures and high temperatures.

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