- #1
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Homework Statement
A light of wavelength 500 nm interferes through a two slit experiment on a screen. The distance between the first minimum and fourth minimum is 1.68 cm. Find the distance between the central maximum and first order maximum.
Homework Equations
d*sin(θ) = nλ = Δ
d = distance between slits
Δ = path difference
sin(θ) = tan(θ)
tan(θ) = x / L
x = distance between orders
L = distance between slits and screen
The Attempt at a Solution
We can find the path difference between the first and fourth minimum by:
(3.5)λ which is 0.000175 cm. (I converted 500 nm to 0.00005 cm).
So we can get: ##\frac{0.000175 cm}{d} = \frac{1.68 cm}{L} = tan(θ_1) = sin(θ_1)##.
We need to find: ##\frac{0.00005 cm}{d} = \frac{x}{L} = tan(θ_2) = sin(θ_2)##
But it doesn't look like we have enough information. How can I solve this? Can I use the ratio d / L to set the equation ##\frac{0.000175}{1.68} = \frac{0.00005}{x}##?