Displacement given the acceleration

In summary: The car has gone 3m since the light turned green and the motorcycle has gone 20m since the light turned green.
  • #1
Guillem_dlc
184
15

Homework Statement


How could I get the distance traveled by a vehicle having only its constant acceleration as data?

Homework Equations


I know that the acceleration is the derivative of the velocity and the velocity is the derivative of the position.

The Attempt at a Solution


I don't know how to find the position because I have only the acceleration.
 
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  • #2
use equations of kinematics
 
  • #3
Guillem_dlc said:
having only its constant acceleration as data?
You can safely assume that the initial displacement is zero from the way the question is framed.

Unfortuately, you cannot justifiably make such an assumption about the initial velocity. This leave the problem without a solution.
 
  • #4
At the instant when a traffic light turns green, a car starts to move with a constant acceleration of 3ms ^ 2, at that same moment, a motorcycle is placed at its speed at a constant speed of 20ms. The two vehicles continue advancing past the traffic light.

Calculate the distance, measured from the traffic light, which runs until it is at the height of the motorcycle

The speed of the car at the time it is at the height of the motorcycle
 
  • #5
What you have just posted is not quite the problem in post #1.

Guillem_dlc said:
which runs until it is at the height of the motorcycle

As it stands, this does not quite make sense. Are you sure that height is the word you want heree?
 
  • #6
Dr.D said:
What you have just posted is not quite the problem in post #1.
As it stands, this does not quite make sense. Are you sure that height is the word you want heree?
which runs until it is at the same distance of the motorcycle.

Thanks
 
  • #7
Guillem_dlc said:

Homework Equations


I know that the acceleration is the derivative of the velocity and the velocity is the derivative of the position.

The Attempt at a Solution


I don't know how to find the position because I have only the acceleration

The opposite of differentiation is integration. You will need to think about the constants.
 
  • #8
You need to specify the initial conditions of position and velocity to solve the problem. Then it is just an application of the 1D kinematic equation. x(t) = x(0) + v(0) t + a t^2 / 2.
 
  • #9
Guillem_dlc said:
At the instant when a traffic light turns green, a car starts to move with a constant acceleration of 3ms ^ 2, at that same moment, a motorcycle is placed at its speed at a constant speed of 20ms. The two vehicles continue advancing past the traffic light.

Calculate the distance, measured from the traffic light, which runs until it is at the height of the motorcycle

The speed of the car at the time it is at the height of the motorcycle
Just to clean up the English a bit, I think you are saying that the car and motorcycle pass the traffic light at the same time, the car accelerating from rest at 3m/s2 and the motorcycle moving at a constant 20 m/s.
Suppose they meet again time t later. How far has each gone?
 
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Related to Displacement given the acceleration

What is displacement?

Displacement is a measure of the distance and direction an object has moved from its starting point.

What is acceleration?

Acceleration is the rate at which an object's velocity changes over time. It is typically measured in meters per second squared (m/s²).

How is displacement related to acceleration?

Displacement is directly related to acceleration. The greater the acceleration, the greater the displacement of an object will be over a given time period.

What is the equation for calculating displacement given acceleration?

The equation for calculating displacement given acceleration is d = v0t + 1/2at², where d is displacement, v0 is initial velocity, t is time, and a is acceleration.

Can displacement be negative?

Yes, displacement can be negative. This indicates that the object has moved in the opposite direction of its starting point.

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