Determine whether or not is a Hermitian operator

HermitianIn summary, the operator F is defined by Fψ(x)=ψ(x+a) + ψ(x-a), where a is a nonzero constant, and it is being questioned whether or not F is a Hermitian operator. The steps to determine this involve showing that F is bounded, so the adjoint of it exists, and then checking the hermiticity condition in integral form. This can be done by exchanging the argument under the complex conjugate sign and showing that F is equal to its transpose.
  • #1
dje
2
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Homework Statement



The operator F is defined by Fψ(x)=ψ(x+a) + ψ(x-a), where a is a nonzero constant. Determine whether or not F is a Hermitian operator.


Homework Equations



∫(x+a)d/dx + (x-a)d/dxψ



The Attempt at a Solution



f = (1=ax) + (1-ax)ψ

What are the steps I need to do to figure this out. Thanks.
 
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  • #2
No matter the value of a, one can show that F is bounded, so the adjoint of it exists. Then all you need is to check is the hermiticity condition in integral form:

[tex] \int dx \psi^{*}(x) F\psi(x) = ? [/tex]

Try to get the psi with exchanged argument under the complex conjugate sign.
 
  • #3
I am not sure of these steps but I will try. Can you show me if I am still not understanding this. thanks.

Fψ(x)=Fψ(x+a) + ψ(x-a) Fτ= F to be Hermitian
Fψ (x+a) + (x-a) = F dt/dx? (x+a) + (x-a)

= F dt/dx (x + a) + (x-a)

∫(x+a)d/dx + (x-a)d/dx ψ



F τ= (1+ax)ψ + (1-ax)ψ



KEY= * below/symbol I am wanting here is circle with vertical line through it.
(θ*/ψ) = (ψ/θ*)
θ* (x) ψ(x+a) + ψ(x-a) dt/dx dx
= ψ(x +a) + ψ (x-a) dθ*/dx dx

Solution- F is Hermitian operator Fτ= F
 

Related to Determine whether or not is a Hermitian operator

1. What is a Hermitian operator?

A Hermitian operator is a mathematical operator that satisfies the property of self-adjointness, meaning that it is equal to its own conjugate transpose. In other words, if we take the complex conjugate of the operator and transpose it, we will get the same operator back.

2. How is a Hermitian operator different from a normal operator?

A normal operator is an operator that commutes with its adjoint, while a Hermitian operator is a special case of a normal operator that also satisfies the property of self-adjointness. This means that a Hermitian operator will always commute with its own conjugate transpose, while a normal operator may or may not.

3. How do I determine if an operator is Hermitian?

To determine if an operator is Hermitian, we need to check if it satisfies the property of self-adjointness. This can be done by taking the conjugate transpose of the operator and comparing it to the original operator. If they are equal, then the operator is Hermitian.

4. What are the applications of Hermitian operators?

Hermitian operators are commonly used in quantum mechanics to represent physical observables such as energy, momentum, and spin. They are also used in linear algebra and functional analysis to study complex vector spaces and operators.

5. Can a non-square matrix be a Hermitian operator?

No, a non-square matrix cannot be a Hermitian operator. In order for an operator to be Hermitian, it must be square, meaning that it has the same number of rows and columns. This is because the conjugate transpose of a matrix can only be taken if the matrix is square.

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