- #1
PrudensOptimus
- 641
- 0
Any errors? Please pick out and explain, thanks.
[tex]\int{}tan^{-1}(x)dx = F(x)[/tex]
[tex]F'(x) = tan^{-1}(x)[/tex]
[tex]\frac{dy}{dx} = tan^{-1}(x)[/tex]
[tex]dy = tan^{-1}(x) dx[/tex]
[tex]tan^{-1}(\frac{dy}{dx}) = tan(x) [/tex]
[tex]\frac{F'(x)}{1+F^{2}(x)} = sec^{2}(x)[/tex]
[tex]F'(x) = sec^{2}(x)[1 + F^{2}(x)][/tex]
[tex]F(x) = tan(x) + \int{}\frac{sin(x)}{cos^{3}(x)}dx[/tex]
[tex]F(x) = tan(x) + \frac{1}{2cos^{2}(x)} + C[/tex]
[tex]\int{}tan^{-1}(x)dx = F(x)[/tex]
[tex]F'(x) = tan^{-1}(x)[/tex]
[tex]\frac{dy}{dx} = tan^{-1}(x)[/tex]
[tex]dy = tan^{-1}(x) dx[/tex]
[tex]tan^{-1}(\frac{dy}{dx}) = tan(x) [/tex]
[tex]\frac{F'(x)}{1+F^{2}(x)} = sec^{2}(x)[/tex]
[tex]F'(x) = sec^{2}(x)[1 + F^{2}(x)][/tex]
[tex]F(x) = tan(x) + \int{}\frac{sin(x)}{cos^{3}(x)}dx[/tex]
[tex]F(x) = tan(x) + \frac{1}{2cos^{2}(x)} + C[/tex]