Conservation of momentum, collisions - what about friction?

In summary, the problem involves two pucks, one with a mass of 3m and the other with a mass of 2m, colliding in an elastic head-on collision on a frictionless surface. The goal is to find the speed and direction of motion of each puck after the collision, in terms of the initial speed of the second puck, u. The principles of conservation of momentum and energy are used to set up a system of equations to solve for the unknowns. It is noted that the effects of friction can be ignored in this scenario due to the short duration of the collision and the small displacement over which friction can act. However, in cases where the force of friction is significant, it must be taken into consideration in
  • #1
gelfand
40
3
I would like to check my understanding for this problem :

A puck with mass ##3m## is stationary on a horizontal friction-less surface. It is
being impacted in an elastic head-on collision by another puck with the mass
##2m## traveling with speed ##u## to the right. Find the speed and direction of
motion of each puck after collision in terms of ##u##

**********

So for this I would note that because there's no friction there's going to be no
loss of momentum, and energy is always conserved.

So for the equality of momentum before and after the collision I will have:

$$
m_1 v_1 + m_2 v_2 =
m_1 u_1 + m_2 u_2
$$

And for the equality of energy I have:

$$
W + PE_0 + KE_0 =
PE_f + KE_f + \text{Energy(Lost)}
$$

Here there's no work being done during the movement of the puck, and there's no
energy lost due to friction. The pucks are on the ground, so there's no
potential energy either, which gives$$
KE_0 = KE_f
$$

The kinetic energy for the system is

$$
\frac{1}{2}m_1u_1^2 +
\frac{1}{2}m_2u_2^2 =
\frac{1}{2}m_1v_1^2 +
\frac{1}{2}m_2v_2^2
$$

I can multiply all by ##2##, set the second term of the LHS to zero and input the
given quantities here.

Once this is done I have a set of simultaneous equations that can be solved.

But what I'm not sure about -

What if there's friction? How do I consider this?

It seems that If I have friction then I'll no longer have

$$
m_1 v_1 + m_2 v_2 =
m_1 u_1 + m_2 u_2
$$

Though I will still have

$$
W + PE_0 + KE_0 =
PE_f + KE_f + \text{Energy(Lost)}
$$But this one equation (energy conservation) wouldn't allow me to solve for two
unknowns?

I see there are other questions appearing that have similar meanings - I have tried to be explicit in my understanding here though, so if there's anything that "doesn't look right" please say.

Thanks
 
Physics news on Phys.org
  • #2
The principle of conservation of momentum still holds if friction is considered, but you would have to add in the momentum that the Earth gains from the friction with the puck.
 
  • #3
gelfand said:
What if there's friction? How do I consider this?
You can almost always ignore the effects of friction that take place during a collision. That is because a collision takes place quickly. There is little time for any frictional force to have an effect on momentum. And there is little displacement over which the frictional force can do any work.

This holds when the frictional force is small relative to the force of the collision. For instance, consider hockey pucks sliding across the surface of a table and colliding. The force of friction between pucks and table is non-zero. But it is small compared to the very high and very brief force of the collision.

In some cases, the force of friction is part and parcel of the collision. Consider, for instance, a rotating rubber ball bounced onto a floor at an angle. The normal force of the ball on the floor during the collision is very brief and very high. Similarly the force of friction during the collision can be very brief and very high. Friction cannot be ignored in such a case.

[If you've ever bounced a "Super Ball" (a highly elastic rubber ball with pretty high friction) onto the floor with some spin, you may have experienced this first hand]
 
  • #4
FactChecker said:
The principle of conservation of momentum still holds if friction is considered, but you would have to add in the momentum that the Earth gains from the friction with the puck.
thanks - could you elaborate a little? I'm not too sure what you're meaning is - or whether you're suggesting considerations such as Earth's mass etc?
 
  • #5
jbriggs444 said:
You can almost always ignore the effects of friction that take place during a collision. That is because a collision takes place quickly. There is little time for any frictional force to have an effect on momentum. And there is little displacement over which the frictional force can do any work.

This holds when the frictional force is small relative to the force of the collision. For instance, consider hockey pucks sliding across the surface of a table and colliding. The force of friction between pucks and table is non-zero. But it is small compared to the very high and very brief force of the collision.

In some cases, the force of friction is part and parcel of the collision. Consider, for instance, a rotating rubber ball bounced onto a floor at an angle. The normal force of the ball on the floor during the collision is very brief and very high. Similarly the force of friction during the collision can be very brief and very high. Friction cannot be ignored in such a case.

[If you've ever bounced a "Super Ball" (a highly elastic rubber ball with pretty high friction) onto the floor with some spin, you may have experienced this first hand]

Cheers - I'm not familiar with the super ball etc.

So we should consider the materials for this type of problem?

If the question was posed **without** the information on the elasticity, would I have had to change my approach ? I mean - I guess that it would still be elastic, but this would be something that I couldn't take for granted. I'm not sure how I would factor that.

I wish I had found this forum at the start of the module rather than two weeks before the exam! :')
 
  • #6
gelfand said:
If the question was posed **without** the information on the elasticity, would I have had to change my approach ?
Without information on elasticity, there are many possible outcomes from the collision. You have two unknowns and only one equation (conservation of momentum). There would have been no way to solve the problem.
 
  • #7
jbriggs444 said:
Without information on elasticity, there are many possible outcomes from the collision. You have two unknowns and only one equation (conservation of momentum). There would have been no way to solve the problem.
ah right ok - thanks.

I wasn't sure if there was some kind of way to test whether it's elastic.
 
  • #8
gelfand said:
thanks - could you elaborate a little? I'm not too sure what you're meaning is - or whether you're suggesting considerations such as Earth's mass etc?
Yes, I'm talking about the mass of the Earth. So that is usually ruled out by saying there is no friction. If you are talking about the heat generated by internal friction, that does not change the principle of conservation of momentum. Heat is random (directionless average) motion with 0 momentum. Kinetic energy can be converted to heat but momentum will not be.
 
  • Like
Likes gelfand
  • #9
FactChecker said:
Yes, I'm talking about the mass of the Earth. So that is usually ruled out by saying there is no friction. If you are talking about the heat generated by internal friction, that does not change the principle of conservation of momentum. Heat is random (directionless average) motion with 0 momentum. Kinetic energy can be converted to heat but momentum will not be.
Ok thanks - I'm not sure that I've seen anything that takes these into consideration. So I think that I'll chalk it up to general knowledge rather than something that (for now) I should apply.
 

Related to Conservation of momentum, collisions - what about friction?

1. What is conservation of momentum?

Conservation of momentum is a fundamental principle in physics that states that the total momentum of a closed system remains constant. This means that the total momentum before a collision is equal to the total momentum after the collision, even if there are external forces acting on the system.

2. How does conservation of momentum apply to collisions?

Conservation of momentum is particularly useful in analyzing collisions between objects. In a collision, the total momentum of the system (the two objects involved) remains the same before and after the collision. This allows us to predict the final velocities of the objects based on their masses and initial velocities.

3. What role does friction play in conservation of momentum?

Friction is a force that opposes motion and can affect the conservation of momentum in a collision. When two objects collide, friction between them can cause a loss of momentum, resulting in a decrease in the final velocities of the objects. This is why it is important to consider friction when analyzing collisions.

4. Does conservation of momentum apply to all types of collisions?

Conservation of momentum applies to all types of collisions, whether they are elastic (where kinetic energy is conserved) or inelastic (where kinetic energy is not conserved). In both cases, the total momentum of the system remains constant, but the distribution of kinetic energy may change due to external forces such as friction.

5. How does the conservation of momentum equation account for the direction of motion?

The conservation of momentum equation takes into account the direction of motion by using vector notation. The momentum of an object is a vector quantity, meaning it has both magnitude and direction. In collisions, it is important to consider the direction of the momentum vectors for each object involved, as this will affect the final velocities of the objects after the collision.

Similar threads

  • Introductory Physics Homework Help
Replies
18
Views
177
  • Introductory Physics Homework Help
Replies
5
Views
812
  • Introductory Physics Homework Help
Replies
4
Views
479
  • Introductory Physics Homework Help
Replies
12
Views
2K
  • Introductory Physics Homework Help
Replies
7
Views
1K
  • Introductory Physics Homework Help
Replies
15
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
850
  • Introductory Physics Homework Help
Replies
12
Views
1K
  • Introductory Physics Homework Help
Replies
15
Views
312
  • Introductory Physics Homework Help
10
Replies
335
Views
8K
Back
Top