Conservation of momentum and frozen pond

In summary, a 730-N man standing on a frozen pond throws a 1.2kg textbook north at a velocity of 5m/s in an attempt to reach the south shore. Using the equation p=mv, the man's momentum is found to be 6kg m/s. Applying conservation of momentum, it is determined that the man's final velocity after throwing the book can be calculated by comparing the initial and final conditions.
  • #1
physics_luver
1
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Homework Statement


A 730-N man stands in the middle of a frozen pond of radius 5m. He is unable to get to the shore of the pond because there's no friction between his shoes and the ice. So the man throws his 1.2kg textbook north horizontally at velocity of 5m/s. How long does it take him to reach the south shore?


Homework Equations


p=mv I'd presume


The Attempt at a Solution


so, the textbook's momentum is p=1.2(5) p=6kg m/s
I got Pstart=Pend
then Pstart of textbook + Pstart of man= Pend of textbook + Pend of man
therefore, 6+73(0?)=6+73(Vf)
then this means Vf of man is zero? I got confused after that...
 
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  • #2
Initially, the textbook also has zero velocity.
 
  • #3
The momentum of the thrown book is equal to and opposite to the momentum of the man after he throws the book. What's his velocity after he throws the book?
 
  • #4
You have the right equation. Just apply conservation of momentum comparing the initial conditions, which are known, to the final conditions. The book's final velocity and mass are known, and so is the man's mass, so this should allow you to find his velocity. (the only unknown in the equation)
 

Related to Conservation of momentum and frozen pond

What is conservation of momentum?

Conservation of momentum is a fundamental law of physics which states that the total momentum of a closed system remains constant. This means that in the absence of external forces, the total momentum before an event will be equal to the total momentum after the event.

How does conservation of momentum apply to a frozen pond?

When a person skates on a frozen pond, the person and the ice are considered a closed system. According to the law of conservation of momentum, the total momentum of the person and the ice before skating will be equal to the total momentum of the person and the ice after skating. Therefore, the person will gain momentum while skating on the ice, but the ice will gain an equal and opposite momentum to maintain the total momentum of the system.

Why does a person move faster on a frozen pond compared to solid ground?

When a person skates on a frozen pond, the friction between the ice and the skates is significantly lower than the friction between the person's shoes and solid ground. This lower friction allows the person to move with less resistance, resulting in a higher speed. Additionally, the person can also push off the ice with their skates, increasing their momentum.

Does conservation of momentum apply to objects moving in different directions on a frozen pond?

Yes, conservation of momentum still applies to objects moving in different directions on a frozen pond. The total momentum of the system will still remain constant, even if the objects have different individual momenta. This is because the total momentum takes into account the direction of motion as well as the magnitude of momentum.

Can the conservation of momentum be violated?

No, the conservation of momentum is a fundamental law of physics and has been proven to hold true in all observed cases. It is a fundamental principle that is used to explain and predict the behavior of objects in motion. Violation of this law would contradict our understanding of how the physical world operates.

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