- #1
kof9595995
- 679
- 2
Say we have two non-commutative operator A, B. Now I have prepared identical systems in eigenstate of A, then I measure the observable of A, and then B immediately after. Then I must have delta A=0, so no matter what delta B is, the product is 0, seems to violate the uncertainty relation?
Another confusion is: I know non-commutative operator A,B must have different sets of eigenfunctions, but is it possible A and B have one or two common eigenfunctions? If so, if we prepare a system in one of the common eigenstates, two observables will be well defined at the same time。
Another confusion is: I know non-commutative operator A,B must have different sets of eigenfunctions, but is it possible A and B have one or two common eigenfunctions? If so, if we prepare a system in one of the common eigenstates, two observables will be well defined at the same time。