Commutator of field operator with arbitrary functions

In summary, the commutator of a field operator with an arbitrary function is a mathematical operation used to describe the interaction between the two. It is calculated using the commutator formula and is significant in determining the properties of a system. It can be zero if the two operators commute, and it is directly related to the Heisenberg uncertainty principle.
  • #1
eudo
29
8
In QFT, the commutation relation for the field operator [itex]\hat{\phi}[/itex] and conjugate momentum is
[tex]
[\phi(x,t),\pi(y,t)] = i\delta(x-y)
[/tex]
Maybe this is obvious, but what would the commutator of [itex]\phi[/itex] or [itex]\pi[/itex] and, say, [itex]e^{i k\cdot x}[/itex] be?
 
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  • #2
It's obviously 0, because ##\exp(\mathrm{i} k \cdot x)## is just a number, which commutes with all operators.
 
  • #3
Of course... Thanks
 

Related to Commutator of field operator with arbitrary functions

1. What is the commutator of a field operator with an arbitrary function?

The commutator of a field operator with an arbitrary function is a mathematical operation that describes how the field operator and the function interact with each other. It is defined as the difference between the product of the field operator and the function and the product of the function and the field operator, with the order of the operation reversed.

2. How is the commutator of a field operator with an arbitrary function calculated?

The commutator of a field operator with an arbitrary function can be calculated using the commutator formula, which is [A, B] = AB - BA, where A and B are operators. In this case, A would be the field operator and B would be the arbitrary function.

3. What is the significance of the commutator of a field operator with an arbitrary function?

The commutator of a field operator with an arbitrary function is significant because it helps to determine the fundamental properties of the system being studied. It also plays a crucial role in quantum mechanics, as it determines the uncertainty relationship between two observables.

4. Can the commutator of a field operator with an arbitrary function be zero?

Yes, the commutator of a field operator with an arbitrary function can be zero. This occurs when the two operators commute, meaning that their order does not affect the final result. In this case, the two operators have a well-defined simultaneous measurement.

5. How does the commutator of a field operator with an arbitrary function relate to the Heisenberg uncertainty principle?

The commutator of a field operator with an arbitrary function is directly related to the Heisenberg uncertainty principle. The uncertainty principle states that the more precisely the position of a particle is known, the less precisely its momentum can be known, and vice versa. The commutator of two observables is proportional to their uncertainties, and the uncertainty principle can be derived from the commutator of the position and momentum operators.

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