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NotMrX
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Suppose somebody put a coke can in the cup holder. The can is a perfect cylinder with radius R and height H. There is a very small airpocket since the can isn't completely full with a pressure, [tex]P_o[/tex]. The car accelerates horizonatlly with a value of A. The soda has a density of [tex]\rho[/tex]. What is the total pressure half way down the coke can?
Here is my attempt:
[tex]\SigmaF_x = mA = P_x*h*2R[/tex]
[tex]\SigmaF_y = 0 = P_o + \rho*g*/frac{H}{2} - P_y[/tex]
[tex]P=\sqrt{P_x^2 + P_y^2}[/tex]
Somethings seems wrong. Does anyone know a better way to do it? Or why this method is wrong?
Here is my attempt:
[tex]\SigmaF_x = mA = P_x*h*2R[/tex]
[tex]\SigmaF_y = 0 = P_o + \rho*g*/frac{H}{2} - P_y[/tex]
[tex]P=\sqrt{P_x^2 + P_y^2}[/tex]
Somethings seems wrong. Does anyone know a better way to do it? Or why this method is wrong?
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