- #1
IAmPat
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Homework Statement
A coin is rolled without slipping on a table top in a straight line. It starts rolling at 3.4 rad/s and slows down at a constant angular acceleration. It is rolling at 1.2 rad/s when it falls off the table edge. If the radius of the coin is 0.011m, and the edge of the table is 1.6m from where the coin started, for how much time did the coin roll?
Homework Equations
Wi = 3.4rad/s
Wf = 1.2rad/s
[tex]\Delta[/tex]X = 1.6m
radius = 0.011m
[tex]\theta[/tex] = [tex]\frac{1}{2}[/tex](Wf + Wi)* t
Wf = Wi) + [tex]\alpha[/tex]*t
The Attempt at a Solution
2*pi* r = 0.691
1.6m / 0.691 = 23.15 full rotations
23.15 = 1/2 (Wf + Wi)*t
23.15 = 1/2 (1.2 + 3.4)*t
...
t = 10.07sec
That didn't work. I assume it has something to do with calculating how many rotations, or the actual angle displacement.