- #1
LagrangeEuler
- 717
- 20
For two different coherent states
[tex]\langle \alpha|\beta \rangle=e^{-\frac{|\alpha|^2+|\beta|^2}{2}}e^{\alpha^* \beta}[/tex]
In wikipedia is stated
https://en.wikipedia.org/wiki/Coherent_state"Thus, if the oscillator is in the quantum state | α ⟩ {\displaystyle |\alpha \rangle } |\alpha \rangle it is also with nonzero probability in the other quantum state | β ⟩ {\displaystyle |\beta \rangle } |\beta \rangle (but the farther apart the states are situated in phase space, the lower the probability is). However, since they obey a closure relation, any state can be decomposed on the set of coherent states. They hence form an overcomplete basis, in which one can diagonally decompose any state. This is the premise for the Sudarshan-Glauber P representation. "
Could you please explain me what is OVERCOMPLETE BASIS?Also, when some authors write ## \langle \alpha|\beta \rangle \neq \delta(\alpha-\beta)## is ##\delta(\alpha-\beta)## Dirac ##\delta## or some type of continuous Kronecker?
[tex]\langle \alpha|\beta \rangle=e^{-\frac{|\alpha|^2+|\beta|^2}{2}}e^{\alpha^* \beta}[/tex]
In wikipedia is stated
https://en.wikipedia.org/wiki/Coherent_state"Thus, if the oscillator is in the quantum state | α ⟩ {\displaystyle |\alpha \rangle } |\alpha \rangle it is also with nonzero probability in the other quantum state | β ⟩ {\displaystyle |\beta \rangle } |\beta \rangle (but the farther apart the states are situated in phase space, the lower the probability is). However, since they obey a closure relation, any state can be decomposed on the set of coherent states. They hence form an overcomplete basis, in which one can diagonally decompose any state. This is the premise for the Sudarshan-Glauber P representation. "
Could you please explain me what is OVERCOMPLETE BASIS?Also, when some authors write ## \langle \alpha|\beta \rangle \neq \delta(\alpha-\beta)## is ##\delta(\alpha-\beta)## Dirac ##\delta## or some type of continuous Kronecker?
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