Circular motion of bead and wire

In summary, a bead with mass m is threaded on a frictionless vertical wire hoop of radius R, which rotates about a vertical axis through its center with a period of revolution T. The problem asks to find the normal force N exerted on the bead by the wire. The equation Fc=mv^2/r can be used to determine the force, but the direction of the acceleration must first be determined.
  • #1
smallittle
2
0

Homework Statement


A bead threaded on a frictionless vertical wire hoop of radius R. The hoop rotates about a vertical axis through its center. Period of revolution of the hoop is T. The bead has a mass m. Find the normal force N exerted on the bead by the wire.

Homework Equations


Fc=mv^2/r

The Attempt at a Solution


Not sure where to start.

Appreciate any help. Thanks.
 

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  • #2
which force do you think will provide the required centripetal force ??

and which one will balance the weight?
 
  • #3
welcome to pf!

hi smallittle! welcome to pf! :wink:

(try using the X2 icon just above the Reply box :wink:)

well, you've drawn both of the forces …

now, so that you can use F = ma, in what direction is the acceleration? :smile:
 

Related to Circular motion of bead and wire

1. What is circular motion of bead and wire?

Circular motion of bead and wire refers to the motion of a small bead or mass attached to a wire that is rotating around a fixed point or axis. The bead moves in a circular path around the wire, maintaining a constant distance from the center of rotation.

2. What causes circular motion of bead and wire?

Circular motion of bead and wire is caused by the centripetal force, which is the force acting towards the center of rotation that keeps the bead moving in a circular path. This force is provided by the tension in the wire, which acts as a centripetal force due to its direction towards the center of rotation.

3. How is circular motion of bead and wire related to centripetal acceleration?

Circular motion of bead and wire is directly related to centripetal acceleration, as the centripetal force that causes the circular motion also produces the centripetal acceleration. This acceleration is directed towards the center of rotation and is always perpendicular to the velocity of the bead.

4. What factors affect the circular motion of bead and wire?

Several factors can affect the circular motion of bead and wire, including the mass of the bead, the length of the wire, the speed of rotation, and the tension in the wire. Changes in any of these factors can alter the centripetal force and therefore affect the motion of the bead.

5. What is the difference between circular motion of bead and wire and circular motion of a planet around the sun?

While both involve circular motion, the circular motion of bead and wire is caused by a centripetal force provided by the tension in the wire, while the circular motion of a planet around the sun is due to the gravitational force between the two bodies. Additionally, the circular motion of a planet is affected by other factors such as the mass and distance of the planet from the sun, while the circular motion of bead and wire is primarily influenced by the length and tension of the wire.

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