- #1
unscientific
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We all know that in the lab frame observing a charge moving along x-axis, we see an electric field ##E = \frac{Q}{4\pi \epsilon_0 x^2\gamma^2}##, picking up an extra factor of ##\gamma^2## at the bottom.
Assuming no external fields are present, what would the charge see in its own rest frame? It should see zero electric field, right? Since in the charge's rest frame, it only sees the lab frame moving and nothing else.
Assuming no external fields are present, what would the charge see in its own rest frame? It should see zero electric field, right? Since in the charge's rest frame, it only sees the lab frame moving and nothing else.