- #1
famallama
- 9
- 0
Homework Statement
The actual problem is
Find a basis for the null-space of the matrix
(1 0 1 2 1)
(0 1 2 0 1)
(0 1 -1 3 1)
Homework Equations
there are no relevant equations.
The Attempt at a Solution
I attempted to get the matrix into RREF i got
(1 0 3 0 1)
(0 1 2 0 1)
(0 0 -1 1 0)
Each row consisting of a different variable x1, x2, x3, x4, x5, respectively, I do not see an issue with using x4 as a pivot and using x3 as an open variable. Am i totally wrong in my assumption that the only thing that dictates where the variables are in the matrix are in fact their position in the original equation? so I switch the third and fourth column still calling them the same variable? Isn't this like if i were to have an equation x=2y+5g+j is the exact same equation as x=5g+j+2y? I ended up with the answer of
(-s-3t) (-3) (-1)
(-s-2t) (-2) (-1)
x=( t )=t(1 )+s(0 )
( t ) (1 ) (0 )
( s ) (0 ) (1 )
I stopped here because i didn't study right, but i got a 0 on it because i considered my RREF to be correct. Basically my biggest question is why am in not aloud to switch the columns in a matrix? I am aloud to switch the rows around if i please, but not being able to do the columns as well does not seem right to me.