Can someone help me to identify the formula on the attached image?

In summary, the conversation discusses a MATLAB assignment and the difficulties the speaker is having with the theory portion. The tutor provided an equation, which the speaker is unsure of its exact name. The equation is explained to be the heat equation and when multiplied by alpha, it gives the standard form. The speaker is confused about why alpha is divided by 1 in the second equation. The tutor clarifies that the two equations are equivalent. The conversation ends with a reminder to post similar problems in the appropriate homework sections.
  • #1
t0mm02
49
0
Homework Statement
2D diffusion equation model using the Explicit Finite Difference Method
Relevant Equations
Lapace Equation, 2D Diffusion Equation
I have to do a MATLAB assignment but when it comes to the report (the theory) I am having quite a lot of problems. My tutor used this formula that I am going to attach:
139785274_10221322680269558_4797605297380943788_n.jpg


However, I don't know if that equation is the Laplace equation, the 2D Heat Diffusion equation, or what exactly that is as I can not find it anywhere like he wrote it on there.
 
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  • #2
That's the heat equation. Multiplying both sides by [itex]\alpha[/itex] gives the standard form [tex]
\frac{\partial T}{\partial t} = \alpha\left(\frac{\partial^2 T}{\partial x^2} +
\frac{\partial^2 T}{\partial y^2}\right)[/tex]
 
  • #3
pasmith said:
That's the heat equation. Multiplying both sides by [itex]\alpha[/itex] gives the standard form [tex]
\frac{\partial T}{\partial t} = \alpha\left(\frac{\partial^2 T}{\partial x^2} +
\frac{\partial^2 T}{\partial y^2}\right)[/tex]
If it was only alpha in stead of 1/alpha I would understand it. Why is it 1/alpha?
 
  • #4
t0mm02 said:
If it was only alpha in stead of 1/alpha I would understand it. Why is it 1/alpha?
What is it you don't understand? These two equations are equivalent.
$$\frac{\partial T}{\partial t} = \alpha\left(\frac{\partial^2 T}{\partial x^2} +
\frac{\partial^2 T}{\partial y^2}\right)$$
$$\frac 1 \alpha\frac{\partial T}{\partial t} =\frac{\partial^2 T}{\partial x^2} +
\frac{\partial^2 T}{\partial y^2}$$

By the way, problems involving derivatives or partial derivatives are NOT precalculus. Please post any such problems in the Calculus & Beyond homework section or in one of the Physics homework sections.
 

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