- #1
Alimarin
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Homework Statement
A stuntman must jump in a pool from a 50.0 meter tall building. The pool is a horizontal distance of 21.0 meters from the base of the building.
a) What is the initial velocity of the stuntman to be able to land in the pool?
b) Do you think this velocity is reasonable for a human?
c) Realistically, how tall must this building be for the stuntman to be able to make the landing safely?
Homework Equations
Vf^2 = Vi^2 + 2aΔx
Vf = Vi + aΔt
Xf-Xi = Δx
Given:
Xix = 0m
Xfx = 21m
Xiy = 50m
Xfy = 0m
Δx = 21m
Δy = -50m
a= -9.81m/s^2
Viγ = 0m/s
Relevant Unknowns:
Δt = ?
Vfγ = ?
The Attempt at a Solution
Vf^2 = Vi^2 + 2aΔx
Vf^2 = 0^2 + 2(-9.81m/s^2)(-50m)
Vf^2 = 2(9.81m/s^2)(50m)
Vf^2 = 981
Vf = 31.3 m/s
Vf = Vi + aΔt
31.3 = 0 + (-9.81m/s^2) Δt
31.3 = -9.81m/s^2 (Δt)
31.3 = Δt
-9.81m/s^2
Yeah, you see the issue, I made a stupid mistake and my brain is on 0 hours of sleep. and I have school in 1 hour.