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MVPhysics
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Homework Statement
There is a vertical 10 inch pipeline with a disc hanging in it. The disc weighs 7.3 kg. There is a flow coming from the opposite direction (water with density 1017.17 kgm/m3) coming at 2250 gpm at 198 psi in the opposite direction (moving up through a pipe). Is there sufficient force to open the free hanging disc? What is the minimum flow rate (in gpm) needed to raise the disc? Delta P is 5 to 7 psi.
b. how about 1680 gpm at 122 psi ?
Homework Equations
None provided, but equations used below.
The Attempt at a Solution
First I calculated the Force of the disc which would be 7.3kg (9.81 m/s2) = 71.613 kg m/s2
The flow rate of 2250 gpm was converted to 0.142 m3/s
0.142 m3/s * 1017.17 kg/m3 = 144.43 kg/s
The area of the pipe is A=∏r2 , so 78.5398 in2 or 0.05067 m2
I am not sure what the next step would be in comparing a Force (exerted by the disc and gravity) to the Force exerted by a flow rate.
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