- #1
John Ker
- 16
- 1
- Homework Statement
- An electron in a Hydrogen atom moves around in a circular orbit of radius 0.53 x 10^-10 m. Suppose the hydrogen atom is transported into a magnetic field of 0.80 T, where the magnetic field is parallel to the orbital angular momentum.
At what frequency does the electron revolve in the magnetic field?
What is the associated speed of the electron? Assume that the radius of the orbit remains constant.
- Relevant Equations
- V = mv^2/R
f = v/r
f = qvb
So my thought process is as follows, since the initial centripetal force and the second magnetic force are working together, we can set up an equation to calculating final frequency.
However, I am struggling with how this can be done given so little numbers.
mvi^2/r + qvB = mv^2/r
Am I on the right track? Can someone please direct me.
Thanks!
However, I am struggling with how this can be done given so little numbers.
mvi^2/r + qvB = mv^2/r
Am I on the right track? Can someone please direct me.
Thanks!