- #1
Cristiano
- 33
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This is a question about the well known trigonometric problem of the wind triangle, but my problem is just the calculation of the head wind component.
I don't know how to write a general procedure to find the angle between the wind and the speed of the aircraft (the so called ground speed).
Suppose that the wind direction WD= 120° and the ground track GT= 40°; the wind direction is always *from* x degrees, then I need to consider WD + 180= 300; the angle is GT - 300 + 360= 100°.
Now suppose that WD= 40° and GT= 120°; the above formula doesn't work; in this case I just need to do (WD + 180) - GT.
Please, could someone help me in finding a general procedure to do that?
Thank you
I don't know how to write a general procedure to find the angle between the wind and the speed of the aircraft (the so called ground speed).
Suppose that the wind direction WD= 120° and the ground track GT= 40°; the wind direction is always *from* x degrees, then I need to consider WD + 180= 300; the angle is GT - 300 + 360= 100°.
Now suppose that WD= 40° and GT= 120°; the above formula doesn't work; in this case I just need to do (WD + 180) - GT.
Please, could someone help me in finding a general procedure to do that?
Thank you