Calculating Electric Potential and Field for a Charged Disk

In summary, the problem asks for the potential and electric field at point P due to a continuous charge distribution of a disk with a surface charge x. For part A, we use the formula V(P) = (1/4πε₀)∫(σ/r)dA and for part B, we use the formula E(P) = (1/4πε₀)∫(σ∙r̂/r²)dA. The diagram is attached for reference. The attempt at a solution involves trying to relate the given variables and using the equations, but the angles are causing confusion. Further explanation and a step-by-step approach would be helpful in solving this problem.
  • #1
pakman2012
2
0

Homework Statement



2. a) Find the potential due to a continuous charge distribution of a disk with a surface charge, x, at point P.
b) Find the electric field for part A using: attached formula .

Diagram attached.

Homework Equations



attached.

The Attempt at a Solution


Well my first clue was to trying to relate the variables given in the problem and diagrams in relation to potential. I wasn't really able to figure out a way to do so.
 

Attachments

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  • Equation 2.bmp
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  • #2
For part B, I thought of using the equation given and plugging in the variables from the diagram. However, the angles are confusing me. It would be great if someone could explain how to approach this problem and break it down into steps. Thank you! \begin{align}V(P) &= \frac{1}{4\pi\epsilon_0}\int\frac{\sigma}{r}\,dA\\E(P) &= \frac{1}{4\pi\epsilon_0}\int\frac{\sigma\mathbf{\hat{r}}}{r^2}\,dA\end{align}
 
  • #3
However, for part a), the potential due to a continuous charge distribution can be found using the equation V = kQ/r, where k is the Coulomb's constant, Q is the total charge of the disk, and r is the distance from the disk to point P. For part b), the electric field can be found using the formula E = kQ/r^2, where r is the distance from the disk to point P. It is important to note that the electric field is a vector quantity, so its direction must also be taken into account. Additionally, the surface charge density, x, can be used to find the total charge of the disk, Q, by multiplying it by the area of the disk. The diagram attached can also be used to visualize the setup and determine the direction of the electric field at point P.
 

Related to Calculating Electric Potential and Field for a Charged Disk

1. What is a potential question of a disk?

A potential question of a disk refers to the various questions that may arise regarding the properties, functions, or uses of a disk in relation to a specific context or field of study. These questions may aim to explore the potential of a disk in terms of its capabilities, limitations, or impact.

2. How do you determine the potential of a disk?

The potential of a disk can be determined through various methods such as conducting experiments, analyzing data, and consulting experts in the field. It involves evaluating the disk's features, performance, and potential applications to gain a better understanding of its capabilities.

3. What factors affect the potential of a disk?

The potential of a disk can be influenced by several factors, including its design, materials used, size, and intended use. Other external factors such as environmental conditions and technological advancements may also play a role in determining the potential of a disk.

4. How can the potential of a disk be optimized?

The potential of a disk can be optimized by continuously researching and developing new technologies and techniques to improve its design and performance. Additionally, considering the needs and demands of the target audience and incorporating their feedback can also help in maximizing the potential of a disk.

5. What are some potential applications of a disk?

A disk has a wide range of potential applications, including data storage, software installation, operating systems, and multimedia content distribution. It can also be used in various industries such as healthcare, education, finance, and entertainment, for different purposes such as data backup, data analysis, and data transfer.

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