Matt766 said:Homework Statement
Treat the atmosphere as an ideal gas with a uniform temperature of 200 K. Find the density at 20 km.
R= 260 N*m/(kg*k)
g= 3.92 m/s^2
rho(0)= 0.015 kg/m^3[/B]
Homework Equations
P=rho*R*T
dp/dz= -rho*g[/B]
The Attempt at a Solution
I found the pressure at ground level using P=rho*R*T
P=(0.015 kg/m^3) (260 N*m/(Kg K)) (200 K) = 780 N/m^2
I'm not sure how to proceed from here.[/B]
Matt766 said:Homework Statement
Treat the atmosphere as an ideal gas with a uniform temperature of 200 K. Find the density at 20 km.
R= 260 N*m/(kg*k)
g= 3.92 m/s^2
rho(0)= 0.015 kg/m^3
The density of high altitude air refers to the amount of mass per unit volume of air that is present at high altitudes. It is affected by factors such as temperature and air pressure.
The density of high altitude air is significantly lower than that of air at sea level. This is because as altitude increases, the air molecules are more spread out and there is less atmospheric pressure pushing down on them.
As altitude increases, the density of air decreases. This is due to the fact that as air rises, it is subject to lower atmospheric pressure which causes the air molecules to spread out.
Temperature has an inverse relationship with the density of high altitude air. As temperature increases, the air molecules gain more energy and spread out, resulting in a decrease in density.
The density of high altitude air is important for a variety of reasons. It affects the performance of aircraft at high altitudes, as well as the behavior of weather systems and the Earth's climate. It also plays a role in determining the amount of oxygen available for breathing at high altitudes.