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user5 said:Thus it is going to be tanα=(L2-X2)0.5/X? With 2Tsinα=F it seems to give the right answer, however in the "student solution" they refer to that problem as having 2Tcosα=F, Am I right this time?
Does it matter where I decide to place α ?
user5 said:1. From the start x=L thus is the acceleration infinite?
2. Is ax changing while F is constant?
Acceleration with tension refers to the change in velocity of an object as a result of the force of tension acting on it. This can occur when an object is being pulled or stretched by a force, causing it to accelerate in the direction of the force.
In order to calculate acceleration with tension, you will need to know the mass of the object that is being pulled or stretched, as well as the force of tension acting on it. The formula for acceleration with tension is a = F/m, where a is the acceleration, F is the force of tension, and m is the mass of the object.
There are several factors that can affect acceleration with tension, including the mass of the object, the force of tension, and the direction of the force. Additionally, the presence of any other forces acting on the object can also impact its acceleration with tension.
Acceleration with tension is closely related to Newton's laws of motion, specifically the second law which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. This means that as the force of tension increases, the acceleration of the object will also increase, and vice versa.
Yes, acceleration with tension can be negative. This occurs when the force of tension is acting in the opposite direction of the object's motion, causing it to decelerate or slow down. In this case, the acceleration would be represented by a negative value in the formula a = F/m.