Calculate the y component of the electric field at a generic point(x,y)

In summary, the conversation discusses the placement of an electric dipole in the x-y plane and the calculation of the electric field at a generic point (x, y) on the plane. The solution involves defining r(subscript +) and r(subscript -) as the vectors connecting the point defined by r and the two points (+a, 0) and (-a, 0), and calculating their magnitudes. The y component of the electric field is then calculated using the field equation from a point charge.
  • #1
blueyellow

Homework Statement



an electric dipole is placed in the x-y plane, with the positive charge +q placed in position (+a, 0) and the negative charge -q placed in position (-a, 0)

define r(subscript +) and r(subscript -) the vectors connecting the point defined by r and the two points (+a, 0) and (-a, 0), and r(subscript+) and r(subscript -) their magnitudes; calculate the y component of the electric field at a generic point (x, y) of the plane as a function of r(subscript +) and r(subscript -) (it is quicker to use directly the field equation from a point charge than using the potential)

The Attempt at a Solution



E=-gradV=q/(4 pi epsilon0)(1/(r^2)) r-hat

E=q/(4pi epsilon0) [(1/([r(+)]^2 +(x+a)^2))+(1/([r(-)]^2 + (x-a)^2))]
 
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  • #2
In the above was a hint:

"... (it is quicker to use directly the field equation from a point charge than using the potential) ... "

The first line of your solution you have E=-gradV ...

I think you are to just add two electric vectors?
 
  • #3
sorry, I still don't understand. where have I gone wrong?
 

Related to Calculate the y component of the electric field at a generic point(x,y)

1. How do you calculate the y component of the electric field at a generic point?

To calculate the y component of the electric field at a generic point, you can use the formula: E_y = k*q*(y-y_0)/r^3, where E_y is the electric field in the y direction, k is the Coulomb's constant, q is the charge, y is the y coordinate of the point, y_0 is the y coordinate of the source charge, and r is the distance between the two points.

2. What is the significance of calculating the y component of the electric field at a generic point?

Calculating the y component of the electric field at a generic point allows us to understand the strength and direction of the electric field at that specific point. This is important in determining the movement and behavior of charged particles in the presence of electric fields.

3. How does the y component of the electric field affect the overall electric field at a generic point?

The y component of the electric field, along with the x component, determines the overall strength and direction of the electric field at a generic point. The two components work together to create a vector field, where the direction of the electric field is determined by the direction of the vector at that point.

4. Can the y component of the electric field be negative?

Yes, the y component of the electric field can be negative. This indicates that the direction of the electric field at that point is in the negative y direction. It is important to note that the negative sign does not indicate a decrease in the strength of the electric field, but rather a change in direction.

5. Are there any other factors that can affect the y component of the electric field at a generic point?

Yes, the y component of the electric field can also be affected by the presence of other charges or conducting surfaces nearby. These factors can alter the strength and direction of the electric field at a specific point, and should be taken into consideration when calculating the y component of the electric field.

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