Calculate Max Speed of Truck on Unbanked Curve Without Eggs Sliding

  • Thread starter Paymemoney
  • Start date
  • Tags
    Rotational
In summary: The normal force is the force exerted by the truck on the crate. (It's the same as the weight of the crate, but we're not using the weight here.) Draw a free-body diagram for the crate. What forces act on it?In summary, an astronaut on the surface of the Moon fires a cannon to launch an experiment package, which leaves the barrel moving horizontally. The muzzle speed of the probe must be 1.68km/s for it to travel completely around the Moon and return to its original location in approximately 1.80 hours. In a separate problem, a crate of eggs located in the middle of a flat bed of a pickup truck can safely travel around an unbanked
  • #36
Paymemoney said:
so if i use the F= N - mg

mg = N - mg

9.8 = N -9.8

N= 19.6N

however when i done it this way and i found the velocity to be the right answer as the book.

To answer your question would it be fsmax = [tex]\mu * mg[/tex]
 
Physics news on Phys.org
  • #37
Paymemoney said:
however when i done it this way and i found the velocity to be the right answer as the book.
You might get lucky now and then, but that method makes no sense. Learn how to do it right, then you're good to go no matter what.

To answer your question would it be fsmax = [tex]\mu * mg[/tex]
OK. That's the net force providing the centripetal acceleration. Use Newton's 2nd law to find the velocity.
 
  • #38
do i use the equation [tex]F=\frac{mv^2}{r}[/tex]??
 
  • #39
Paymemoney said:
do i use the equation [tex]F=\frac{mv^2}{r}[/tex]??
Yes, where F is the friction force (in this case).
 
  • #40
ok i understand so:
[tex]\mu * N = \frac{mv^2}{r}[/tex]

[tex]r(\mu * mg) = mv^2[/tex]

cancel m's


[tex]r * \mu * g = v^2[/tex]

then sub in values to get final answer of 14.3m/s
 
  • #41
Exactly.
 

Similar threads

  • Introductory Physics Homework Help
Replies
4
Views
5K
  • Introductory Physics Homework Help
Replies
2
Views
3K
  • Introductory Physics Homework Help
Replies
2
Views
2K
  • Introductory Physics Homework Help
Replies
4
Views
3K
  • Introductory Physics Homework Help
Replies
2
Views
6K
Back
Top