- #1
hobbs125
- 108
- 0
Hi everyone,
Say I have a series DC circuit. The circuit contains a 100V DC source, a switch, a 1.5H inductor, and a 1nF capacitor (all in series).
If I close the switch for 2uS what is the current at that time?
Initially I thought I could rearrange V=L*di/dt to
V*Ton/L = di/dt which would be 100*.000002/.150=1.3mA?
For some reason I am thinking this is not right since the capacitor charge should also effect the current.
Can anyone help me understand and calculate this correctly?
Say I have a series DC circuit. The circuit contains a 100V DC source, a switch, a 1.5H inductor, and a 1nF capacitor (all in series).
If I close the switch for 2uS what is the current at that time?
Initially I thought I could rearrange V=L*di/dt to
V*Ton/L = di/dt which would be 100*.000002/.150=1.3mA?
For some reason I am thinking this is not right since the capacitor charge should also effect the current.
Can anyone help me understand and calculate this correctly?