Blackbody effect hypothetical question

[Badmouton]

According to the blackbody effect, can something be so hot that it emits no visible light?
I say this because the more heated an object is, the more it moves away from the visible light spectrum, does that apply until there is no light at all?

 

[mathman]

Not really. The spectrum of the emitted radiation includes all wavelengths. What happens is that the peak moves to ultraviolet or even x-rays, but it is still visible.

 

[Nabeshin]

As you heat a body, the energy it emits in any particular wavelength band strictly increases, so even though you are proportionally increasing the amount emitted in UV or x-ray, you are still increasing the amount in the visual spectrum.

 

[AtomicJoe]

As you heat a body, the energy it emits in any particular wavelength band strictly increases, so even though you are proportionally increasing the amount emitted in UV or x-ray, you are still increasing the amount in the visual spectrum.

As demonstrated here:-

I would like to know if it ever gets 'blue hot'.

Google says yes - blue stars.

http://outreach.atnf.csiro.au/education/senior/astrophysics/photometry_colour.html

 

[pmacias]

Yes, it is possible for an object to become so hot that it emits no visible light. This phenomenon is known as a blackbody radiator, where the object absorbs and emits all radiation that falls on it. As the temperature of the object increases, the peak of its emission spectrum shifts towards shorter wavelengths, eventually reaching the ultraviolet and then the X-ray region. At extremely high temperatures, the object's emission spectrum may not include any visible light, making it appear black to our eyes. This is due to the fact that at these high temperatures, the object's atoms are excited to such a level that they emit most of their energy in the form of non-visible radiation. However, it is important to note that even at these extreme temperatures, the object will still emit some amount of visible light, just not enough for us to see it.