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keithdow
- 29
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It is well know that it takes pi*m time to go from rest at the surface of a Schwarzschild black to the singularity. How much time does an external observer at infinity experience then in that time? How do I show it?
The falling time for a black hole depends on the mass and distance of the observer from the black hole. Generally, for a non-rotating black hole, the falling time for an external observer is infinite, as the observer will never actually reach the event horizon due to time dilation. However, for a rotating black hole, the falling time can be significantly reduced.
No, the falling time for an external observer cannot be measured as it is infinite for a non-rotating black hole. Even for a rotating black hole, it is difficult to measure due to the extreme gravitational effects near the event horizon.
The falling time for an object inside a black hole is different from an external observer because the object is experiencing the strong gravitational pull of the black hole, while the external observer is not. This means that the object will fall faster towards the singularity compared to an external observer.
Yes, the size and shape of a black hole can affect the falling time for an external observer. For example, a more massive black hole will have a stronger gravitational pull, resulting in a longer falling time for an external observer. Additionally, a rotating black hole can have a shorter falling time due to the effects of frame dragging.
No, there is no maximum falling time for an external observer for a black hole. As long as the black hole exists, the falling time for an external observer will continue to increase, approaching infinity for a non-rotating black hole. This is due to the extreme gravitational effects near the event horizon, which cause time to slow down significantly.