- #1
quackyneudle
Hi,
I am having trouble wrapping my head around a simple (I think?) question about birefringent walkoff:
If the crystal is oriented at some angle such that walkoff is nonzero between e and o beams (in a nonlinear conversion process, for example), it seems to me that reflecting the light straight back after it exits should have the e beam walkoff in the opposite direction as before i.e. towards the o beam, and "compensated". But, I haven't been able to convince myself of this by drawing pictures. Can anyone help provide an explanation about whether this is correct of not, whether through math or visual argument?
Thanks!
I am having trouble wrapping my head around a simple (I think?) question about birefringent walkoff:
If the crystal is oriented at some angle such that walkoff is nonzero between e and o beams (in a nonlinear conversion process, for example), it seems to me that reflecting the light straight back after it exits should have the e beam walkoff in the opposite direction as before i.e. towards the o beam, and "compensated". But, I haven't been able to convince myself of this by drawing pictures. Can anyone help provide an explanation about whether this is correct of not, whether through math or visual argument?
Thanks!
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