- #1
PerilousGourd
- 5
- 0
Why is ##\bar{\psi}=e^{i\theta}\psi##, where ##\theta## is a real number, used as the global gauge transformation? Why ##e^{i \theta}##; what's the physical significance or benefit?
Why is ##\bar{\psi} = e^{i \theta(x)} \psi## the local gauge transformation? What does ##\theta## being a function of ##x## instead of a real number change such that it no longer applies globally?
Thank you in advance for any explanations. I'm sorry if my questions are trivial!
Why is ##\bar{\psi} = e^{i \theta(x)} \psi## the local gauge transformation? What does ##\theta## being a function of ##x## instead of a real number change such that it no longer applies globally?
Thank you in advance for any explanations. I'm sorry if my questions are trivial!