The formula for finding the maximum height of a ball thrown upward is h = (v02 sin2 θ) / (2g), where h is the maximum height, v0 is the initial velocity, θ is the angle of projection, and g is the acceleration due to gravity.
The initial velocity of a ball thrown upward can be calculated using the formula v0 = u cos θ, where v0 is the initial velocity, u is the initial speed, and θ is the angle of projection.
No, the maximum height of a ball thrown upward is different for different angles of projection. The angle of projection affects the initial velocity and the time of flight, which both play a role in determining the maximum height.
Air resistance can decrease the maximum height of a ball thrown upward. As the ball moves upwards, it experiences air resistance which slows it down. This results in a shorter time of flight and a lower maximum height.
Yes, the maximum height of a ball thrown upward can be greater than the initial height if the angle of projection is greater than 45 degrees. In this case, the ball follows a parabolic path and reaches a maximum height before falling back to the ground.