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Homework Statement
This question is from the Australian HSC maths extension 2 test. Q8b)
Let n be a positive integer greater than 1.
The area of the region under the curve y=1/x from x=n-1 to x=n is between the areas of two rectangles.
Show that [tex]e^{-\frac{n}{n-1}}<\left(1-\frac{1}{n}\right)^n<e^{-1}[/tex]
The Attempt at a Solution
The area under the curve is more than the smaller rectangle but less than the larger rectangle.
Thus, [tex]\frac{1}{n}<\int^n_{n-1}\frac{dx}{x}<\frac{1}{n-1}[/tex]
After manipulating somewhat:
[tex]\frac{1}{n}<ln\left(\frac{n}{n-1}\right)<\frac{1}{n-1}[/tex]
[tex]e^{\frac{1}{n}}<\frac{n}{n-1}<e^{\frac{1}{n-1}}[/tex]
but I'm unsure how to get to the answer...